AlexanderBunt because the sensors each need 50Ma for as far as I know…
I assume you stuck with the CNY70s.
Their IR LEDs do not consume 50mA. Rather, they're current devices. They consume approximately 1.25V. (That does not mean they should be attached to an ideal 1.25V source!) And the 50mA value comes from the "Absolute Maximum Ratings" section. You want to give them less than that. I settled on 20mA.
I believe you were using the design where you put a resistor in series with the LED to control the current. That value, along with the forward voltage of the LED, will determine how much power is consumed by each of the LEDs.
Mean Well is a perfectly good power supply manufacturer, but I'd buy supplies much closer to what you actually need, rather than fiddling with trying to drop down from +24VDC to something small. (Anything which can do that without burning up will introduce its own noise and problems.) They manufacture a number of supplies which directly output +5VDC. Maybe even +3.3VDC, though I haven't checked their catalog for that. I suggest fully enclosed supplies.
Ideally, you'd want to have designed it to use a constant current supply for the LEDs, and chained them together in groups of 24. Without knowing exactly how you've done the physical wiring, I can't say if it is possible to go back to that at this point.
CyberGene As to power, I use an iPad charger which is 2.1 A and is ripple free
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RIP you may be able to order it already assembled from a PCB company.
It has a number of through-hole parts, I doubt any of the inexpensive places will assemble the whole thing.